[mod_python] python print

curiosity impels me, if list append is most efficient in concatenating to
the end of a string, how would I use it where I previously had string
concatenation ?  I can only print out the values
surrounded by [[''],[''], etc]:

<code>

import sys

dict1 = {
            '0' : 'zero',
            '1' : 'one',
            '2' : 'two',
            '3' : 'three',
            '4' : 'four',
            '5' : 'five',
            '6' : 'six',
            '7' : 'seven',
            '8' : 'eight',
            '9' : 'nine',
            ' ' : '\n',
        }

def convert(numbers):
    w = []
    for argument in numbers:
        w.append([dict1[digit] for digit in argument])
#        w += ''.join([dict1[digit] for digit in argument])
    return w

</code>

On Tue, 10 Jun 2003, Jonathan Gardner wrote:

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> On Tuesday 10 June 2003 07:49, Scott Russell wrote:
> > On Tue, 2003-06-10 at 09:35, Jonathan Gardner wrote:
> > > B)
> > > 	s = []
> > > 	s.append('something')
> > > 	s.appent('something more')
> > > 	...
> > > 	print "".join(s)
> > >
> > > B is far more efficient than A. This really shows up when you are
> > > concatenating hundreds or more elements. Anything below that, it really
> > > doesn't make too much of a difference.
> > >
> >
> > Momma always says, "Make sure you can read it first, only optimize it
> > after you profile." :)
> >
>
> You're right. This particular algorithm has been tested and profiled. I gave
> you the numbers I have found when I have done profiling. That is why I use
> this almost everywhere I have to concatenate multiple strings together. While
> it is true you shouldn't spend too much time optimizing on your first
> iteration of writing your code, it is silly to use methods you know are
> inefficient when comparable methods that are efficient exist and are
> well-tested. It just makes more work for the second and beyond iterations.
>
> - --
> Jonathan Gardner <jgardner at jonathangardner.net>
> (was jgardn at alumni.washington.edu)
> Live Free, Use Linux!
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