Graham Dumpleton
graham.dumpleton at gmail.com
Mon Apr 20 01:48:54 EDT 2009
2009/4/20 rahul <rahul.warhekar at edisphere.com>: > Is silent mode Installation of this package is possible or not? > > Or do I need to use latest version for silent installation of mod_python. Why do you think there is a silent mode? Is it documented somewhere in the mod_python documentation that there is such a mode? FWIW, mod_python appears to use Python native feature to build a exe using 'bdist_wininst' option to Python distutils. So, perhaps try and track down on Python web site (www.python.org) whether that feature produces installers which can operate in a silent mode. If distutils doesn't support that, then not likely to be in there. You might also go to comp.lang.python newsgroup on Google Groups and ask there whether installers created with distutils support a silent mode. You will have to be specific about what you asking, ie., mention distutils and the 'bdist_wininst' option and whether it supports silent installers. There is no point asking there about mod_python as they will not answer you. BTW, if people don't answer it is likely that no one knows. Thus there is no point asking time and time again, it just annoys people. You also haven't answered the question of why you are using an old version of mod_python when there is a newer version available. Older versions tend not to be supported and would generally expect that you be using latest version. Graham > Thanks, > Rahul Warhekar > > -----Original Message----- > From: Graham Dumpleton [mailto:graham.dumpleton at gmail.com] > Sent: Sunday, April 19, 2009 5:11 AM > To: rahul > Cc: mod_python at modpython.org > Subject: Re: [mod_python] mod_python Installation > > 2009/4/18 rahul <rahul.warhekar at edisphere.com>: >> Hello All, >> >> >> >> I have my application in python which requires mod_python, so I have two >> questions, >> >> >> >> 1) Can I distribute mod_python-3.2.8.win32-py2.4.exe package with my >> code? > > Why are you using an old known buggy version of mod_python? > > Graham > >
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