[mod_python] Implementing Range Retrieval Requests

Haha, maybe I should scroll down. :-)

You do setup the setattr after all.

Graham

2008/8/19 Graham Dumpleton <graham.dumpleton at gmail.com>:
> 2008/8/19 Samuele Kaplun <Samuele.Kaplun at cern.ch>:
>> Dear Grahm,
>>
>> Il Tuesday 12 August 2008 12:17:37 Graham Dumpleton ha scritto:
>>>
>>> You would need the following to be implemented:
>>>
>>>   https://issues.apache.org/jira/browse/MODPYTHON-238
>>>
>>> If it is your own application on your own server, you could perhaps
>>> modify mod_python source code to address the issue.
>>>
>>> Graham
>>
>> pardon my ignorance, but do you mean that if I patch mod_python in order to
>> have a setter for req.chunked and req.connection.keepalive, I could be able
>> to disable chunked encoding even if content length is not specified,
>
> That is what my analysis in JIRA issues suggests.
>
>> thus being able to manually build multirange responses?
>
> Don't know about the multirange response side of things. :-)
>
>> I tried to patch mod_python, as you suggested, creating the patches I'm
>> attaching. For the time being I'm still encountering some errors, that I
>> still need to investigate (they are probably related to my implementation of
>> multirange).
>>
>> If you think my patches are enough for enabling writing support for chunked
>> and keeplive (thus fulfilling MODPYTHON-238 issue), I'd be glad if you would
>> like to accept them for integration into mod_python.
>
> Wouldn't you also need to change:
>
>    {"chunked",      (getter)getreq_recmbr, NULL, "Sending chunked
> transfer-coding", "chunked"},
>
> So that setter, rather than being NULL is:
>
>  (setter)setreq_recmbr
>
> The connection object hasn't previously had writable members so not
> setup same way. Thus not sure how to enable member as writable without
> trying it.
>
> Not on machine where can play with source code at moment, can only
> view it via web from repository.
>
> Do you changes actually allow you to set values, then read back to
> confirm changed?
>
> Graham
>