Christopher Sean Hilton
chris at vindaloo.com
Fri Apr 12 00:45:08 EST 2002
Thanks, I'll try this out tommorow. Chris On Thu, Apr 11, 2002 at 04:14:14PM -0400, Tom Emerson wrote: > Christopher Sean Hilton writes: > > I'm trying to create a script to handle a file upload from a form with > > mod_python. I know that I should be looking into the util module but I've > > really got no clue about how to get started. Has anyone got some words of > > wisdom to put me on the right track? > > I've done this using publisher: it's certainly the easiest way. > > Given a form along the lines of: > > <form action="process.py/doit" method="POST" enctype="multipart/form-data"> > <b>Filename</b>: <input type="file" name="file"> > </form> > > And a form handler "doit" in process.py: > > def doit(req, file): > # ... > > The 'file' argument is a file object representing the uploaded file: > you can read from this as you would any other file. > > You should check to make sure that the file has a non-zero length: > > import os, stat > statinfo = os.fstat(file.fileno()) > if statinfo[stat.ST_SIZE] > 0: > # process the text > else: > # it's an empty file, or it didn't exist! > > You should also look at the content type of the uploaded file. You can > access this via the form table in the request record: > > _file = req.form['file'] > if _file.type == "text/plain": > # process plain text > > That should be enough to get you started, I expect. > > -tree > > -- > Tom Emerson Basis Technology Corp. > Sr. Computational Linguist http://www.basistech.com > "Beware the lollipop of mediocrity: lick it once and you suck forever" > -- Chris Hilton chilton-at-vindaloo-dot-com ------------------------------------------------------------------------ "All I was doing was trying to get home from work!" -- Rosa Parks
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